19y+6=36y^2

Solution for 19y+6=36y^2 equation:

19y+6=36y^2

We move all terms to the left:

19y+6-(36y^2)=0

determiningTheFunctionDomain
-36y^2+19y+6=0

a = -36; b = 19; c = +6;
Δ = b2-4ac
Δ = 192-4·(-36)·6
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-35}{2*-36}=\frac{-54}{-72}
=3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+35}{2*-36}=\frac{16}{-72}
=-2/9
$